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functioncountApplesAndOranges(s,t,a,b,apples,oranges){// Write your code hereletcounter=[0,0];apples.map(ap=>{if(((ap+a)>=s)&&((ap+a)<=t))counter[0]++;})oranges.map(or=>{if(((or+b)>=s)&&((or+b)<=t))counter[1]++;})returnconsole.log(counter.join('\n'));}
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Apple and Orange
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This is my approach: