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Here's another one ;)
print([d+a>=s and d+a<=t for d in apple].count(True))
print([b+d>=s and b+d<=t for d in orange].count(True))
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Apple and Orange
You are viewing a single comment's thread. Return to all comments →
Here's another one ;)
print([d+a>=s and d+a<=t for d in apple].count(True))
print([b+d>=s and b+d<=t for d in orange].count(True))