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You may reuse N and ditch i
N
i
Hi, I had not think it, but can be done like this:
#include <iostream> int main() { int N; std::cin>>N; int *A = new int[N]; while(std::cin>>A[--N]); while(A[++N] && std::cout<<A[N]<<' '); delete[] A; return 0; }
This program not gonna work as expected when there is element with value 0.
when you have 7 1 2 4 0 6 0 7
7
1 2 4 0 6 0 7
it will only output 7
I unable to get breaking condition in second while loop;
Arrays Introduction
You are viewing a single comment's thread. Return to all comments →
You may reuse
Nand ditchiHi, I had not think it, but can be done like this:
This program not gonna work as expected when there is element with value 0.
when you have
71 2 4 0 6 0 7it will only output
7I unable to get breaking condition in second while loop;