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  1. Prepare
  2. Algorithms
  3. Strings
  4. Beautiful Binary String
  5. Discussions

Beautiful Binary String

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854 Discussions

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  • mordekaizen
     + 0 comments

    // c#

    public static int beautifulBinaryString(string b)
{       
    string newB = b.Replace("010", "xxx");
    int occur = 0;

    for(int i=0; i<newB.Length; i++)
    {
        if (newB.Substring(i,1) == "x")
        {
            i += 2;
            occur++;
        }
    }

    return occur;
}

  • ugurkurt90
     + 0 comments

    Basic solution

    int beautifulBinaryString(string b) { int result = 0; while (b.find("010")!=string::npos) { ++b[b.find("010")+2]; result++; } return result; }

  • afzal_saiyed931
     + 0 comments
    def beautifulBinaryString(b):
    # Write your code here
    operations = 0
    count = 0
    while count < len(b) - 2:
        if b[count: count+3] == "010":
            operations += 1
            count += 3
            continue
        count+= 1
    return operations

  • yashdeora98294
     + 0 comments

    Here is problem solution in python java c++ c and javascript - https://programmingoneonone.com/hackerrank-beautiful-binary-string-problem-solution.html

  • shiaramoon
     + 0 comments

    python 3

    def beautifulBinaryString(b):
    l = list(b)
    steps = 0
    
    for i in range(len(b)-2):
        if "".join(l[i : i + 3]) == '010':
            steps += 1
            if i + 3 < len(b) and l[i + 3] == '1':
                l[i + 2] = '1'
            else:
                l[i + 1] = '0'
    
    return steps