navjotahuja92 this :)
i, j, k = [int(x) for x in input().split()] beautifulDays = [1 for day in range(i, j+1) if (day - int(str(day)[::-1])) % k == 0] print(sum(beautifulDays))
kevinmathis08 Nice solution! Here is my not so elegant solution, however maybe easier to understand for beginners..
i,j,k = [int(x) for x in input().split()] count = 0 for x in range(i,j+1): if (x - int(str(x)[::-1])) % k == 0: count += 1 print(count)
himaja97 [deleted]
Harshith1995 [deleted]
alpha52omega41 I have done the same thing, python is amazing.....
amylokh Whoa!
Ninja_kx [deleted]coslic Nice, but I don't like the entaglement in beautifulDays of the looping through range with the algorithm itself that decides to put an 1 or not depending on the (day - reverse of the day) is divisible or not by k. I would disentangle the looping and the filtering by the problem condition in 2 separate functions, and the algorithm will become more readable.
Kostyantin_Kon Like I did?
def reverse(n):
m = 0 while n != 0: m = 10 m += n % 10 n = n // 10 print(m) return mdef beautifulDays(i, j, k):
a = range(i,j+1) return sum([1 for x in a if abs(x-reverse(x)) % k == 0])*codded [deleted]sucheetdumbre201 Mine is similar to this!
jaeemhossain I don't understand how your reverse() function works.The algo seems wrong to me.Can you please explain.
patrickdekelly That Lily girl is loony. Get out while you still can Logan! :P
condrint hahahahahah I was cracking up for a minute or so when I had that thought
venkatsaikiran Solution in Java
import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ Scanner in = new Scanner(System.in); int i = in.nextInt(); int j = in.nextInt(); int k = in.nextInt(); int count = 0; for (int a=i;j>a; a++){ StringBuilder temp = new StringBuilder(); temp.append(a); temp=temp.reverse(); String temp1 = temp.toString(); int aRev = Integer.parseInt(temp1); if(Math.abs((a-aRev)%k)==0){ count++; } } System.out.println(count); } }
Akash_Mishraa can you pls explain this line
if(Math.abs((a-aRev)%k)==0)
venkatsaikiran it's the main logic of our program. it is for checking if the day is beautiful or not. here we are checking if the difference of the number and its reverse can be evenly divided by k.
vaibhavpkc whenever the difference of a and reverse a is divisible by the k no. then the count will increase and hence we will get the required result.
singirthi_abhin1 Math.abs() is used to avoid negative result . Hope this helps!
crazypan public class Solution {
public static void main(String[] args) { Scanner in = new Scanner(System.in); int i = in.nextInt(); int j = in.nextInt(); int k = in.nextInt(); int numOfBeautifulDays=0; for(int l=i; l<=j;l++) { if((l-reverse(l))%k ==0) numOfBeautifulDays++; } System.out.println(numOfBeautifulDays); } public static int reverse(int number){ int reverse = 0; while(number!=0){ reverse = 10*reverse +number%10; number = number/10; } reverse += number; return reverse; }}
phyolintun87 Same idea here
srikanth_27 MR.CRAZYPAN
why did you do this reverse += number;
Wasim_AbbaCi to get reverse of number
vaibhavpkc "reverse += number;" can you explain me this part?
samplenhold You don't need to do the absolute value.
crazypan You are right!
Aswath3167 My C Solution......
#include<stdio.h> int main() { int i=0,j=0,k=0,x=0,rem=0,sum=0,count=0; scanf("%d%d%d",&i,&j,&k); for(i;i<=j;i++) { x=i; while(x!=0) { rem=x%10; sum=(sum*10)+rem; x=x/10; } if(abs(i-sum)%k==0) count=count+1; sum=0; } printf("%d",count); return 0; }
UtkarshSWG my code isnt working..please tell me why
int main() { long int i=0,j=0,k=0,m=0,x=0,d=0,r=0; cin>>i>>j>>k; for(m=i;m<=j;m++) { r=0; while(m!=0) { d=m%10; r=r*10+d; m=m/10; } if((abs(r-m)%k)==0) x++; } cout<<x; return 0; }
non_programmer Dude, you are using same m in your code... which will keep on becoming zero after completion from while loop and it will never be equal to j, better try out with this:
include
include
using namespace std; int main() {
long int i=0,j=0,k=0,m=0,x=0,d=0,r=0,m1=0; cin>>i>>j>>k; for(m=i;m<=j;m++) { r=0; m1=m; while(m1!=0) { d=m1%10; r=r*10+d; m1=m1/10; } if((abs(r-m)%k)==0) x++; } cout<<x; return 0;} I hope you got what's wrong.
UtkarshSWG thanks dude...I got it
nayan_7991 in this when the loop run for the first time the vue of m becomes 0. so we again give the value of i to m and so Infinite loop runs
yashwant97 sum=(sum*10)+rem; i dint understand this line can u pls help me out?
jluisg_23 I did it using conversion to string, but now that I see your solution, yours is simpler and faster. I share mine anyways:
#include <stdio.h> #include <stdlib.h> int reversed(int a) { char c, *ptr_b, *ptr_e; char buff[12]; int b; //Integer to string sprintf(buff, "%d", a); //Reversing string ptr_b = buff; ptr_e = buff; while(*ptr_e){ //Moving ptr_e to point the last char in the string ++ptr_e; } --ptr_e; while(ptr_b < ptr_e){ //Reversing c = *ptr_b; *ptr_b = *ptr_e; *ptr_e = c; ++ptr_b; --ptr_e; } //String to integer sscanf(buff, "%d", &b); return b; } int main() { int i, j, k, rev, diff, count = 0; //Input scanf("%d %d %d", &i, &j, &k); //Counting for(int ii = i; ii <= j; ++ii){ rev = reversed(ii); diff = abs(ii-rev); if(diff%k == 0) ++count; } //Output printf("%d\n", count); return 0; }
giovannict73 Beautiful days using beautiful Swift.....
import Foundation let input: [Int] = readLine()!.componentsSeparatedByString(" ").map { Int($0) ?? 0 } let i: Int = input[0] let j: Int = input[1] let k: Int = input[2] var beautifulDays: Int = 0 for integer in i...j { var int2reverse: Int = integer var reversedNum: Int = 0 while int2reverse != 0 { reversedNum = reversedNum * 10 + int2reverse % 10 int2reverse = int2reverse / 10 } let absDiff: Int = max(integer, reversedNum) - min(integer, reversedNum) if absDiff % k == 0 { beautifulDays += 1 } } print(beautifulDays)
jadex1 what happen to i and j? im still learnig swift.
giovannict73 what do you mean ?
jadex1 I see that i, and j are set by the input string. I also see that beautiful days is an int and set to zero. where I get lost is the for integer in i...j. int2reverse and reversedNum don't look like they get set to me. Where do they get their values from? I don't understand how the input value of i and j get into the
for integer in i..j{}
sendsons So here does not support Swift 3 yet? I've used componentsSeparated(by:), and get a error :(
giovannict73 unfortunately Swift 3 here is not supported yet.
rafaelkgobara Nice solution!
What do you think about using tuple here?
let params = readLine()!.components(separatedBy: " ").map{ Int($0)! } let (i, j, k) = (params[0], params[1], params[2])
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