• + 0 comments

    Here is my solution in JavaScript:

    ` let count = 0

    for(let n = i; n <= j; n++){

    const reversed = parseInt(n.toString().split('').reverse().join(''), 10);

    const diff = Math.abs(n - reversed);

    if(diff % k === 0){
    
        count++
    }
    

    }

    return count; `