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importjava.io.*;importjava.util.*;importjava.text.*;importjava.math.*;importjava.util.regex.*;publicclassSolution{publicstaticvoidmain(String[]args){/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */Scannerin=newScanner(System.in);inti=in.nextInt();intj=in.nextInt();intk=in.nextInt();intcount=0;for(inta=i;j>a;a++){StringBuildertemp=newStringBuilder();temp.append(a);temp=temp.reverse();Stringtemp1=temp.toString();intaRev=Integer.parseInt(temp1);if(Math.abs((a-aRev)%k)==0){count++;}}System.out.println(count);}}
it's the main logic of our program.
it is for checking if the day is beautiful or not.
here we are checking if the difference of the number and its reverse can be evenly divided by k.
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int i = in.nextInt();
int j = in.nextInt();
int k = in.nextInt();
int numOfBeautifulDays=0;
for(int l=i; l<=j;l++) {
if((l-reverse(l))%k ==0) numOfBeautifulDays++;
}
System.out.println(numOfBeautifulDays);
}
public static int reverse(int number){
int reverse = 0;
while(number!=0){
reverse = 10*reverse +number%10;
number = number/10;
}
reverse += number;
return reverse;
}
Actually there is no need to introduce "reverse += number".It's working well without the use of it.
here is my code:
import java.io.;
import java.util.;
import java.text.;
import java.math.;
import java.util.regex.*;
public class Solution {
public static int reverse(int a)
{
int reverse = 0;
while(a!=0)
{
reverse = reverse * 10;
reverse = reverse + a%10;
a = a/10;
}
return reverse;
}
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner in = new Scanner(System.in);
int i = in.nextInt();
int j = in.nextInt();
int k = in.nextInt();
//int n = i-j+1;
// int s[] = new int[n];
int count = 0;
for(int a = i;a<j+1;a++)
{
int d= a-reverse(a);
if(d%k==0)
count++;
}
System.out.println(count);
}
That's a good solution but in the for loop instead of
for (int a=i;j>a; a++)
you need to use
for (int a=i;j>=a; a++)
so that it also checks for the value of a itself and will return the correct and required output.In the case what you have done there might be wrong answer for some of the test cases.
HOPE THIS HELPS!!!
Beautiful Days at the Movies
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Solution in Java
can you pls explain this line
it's the main logic of our program. it is for checking if the day is beautiful or not. here we are checking if the difference of the number and its reverse can be evenly divided by k.
whenever the difference of a and reverse a is divisible by the k no. then the count will increase and hence we will get the required result.
Math.abs() is used to avoid negative result . Hope this helps!
public class Solution {
}
Same idea here
MR.CRAZYPAN
why did you do this reverse += number;
to get reverse of number
"reverse += number;" can you explain me this part?
Actually there is no need to introduce "reverse += number".It's working well without the use of it. here is my code: import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;
public class Solution {
}
why do you need "reverse += number;"?
You don't need to do the absolute value.
You are right!
Very well done!!
static int beautifulDays(int i, int j, int k) { int r=0,count=0;
for loop should be this
should be less than or equal to
That's a good solution but in the for loop instead of for (int a=i;j>a; a++) you need to use for (int a=i;j>=a; a++) so that it also checks for the value of a itself and will return the correct and required output.In the case what you have done there might be wrong answer for some of the test cases. HOPE THIS HELPS!!!