We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Loading...
  1. Practice
  2. Algorithms
  3. Implementation
  4. Beautiful Days at the Movies
  5. Discussions

Beautiful Days at the Movies

  • Aswath3167 + 4 comments

    My C Solution......

    #include<stdio.h>
int main()
{
int i=0,j=0,k=0,x=0,rem=0,sum=0,count=0;
scanf("%d%d%d",&i,&j,&k);
for(i;i<=j;i++)
{
x=i;
while(x!=0)
{
rem=x%10;
sum=(sum*10)+rem;
x=x/10;
}
if(abs(i-sum)%k==0)
count=count+1;
sum=0;
}
printf("%d",count);
return 0;
}
    • UtkarshSWG + 2 comments

      my code isnt working..please tell me why

      int main() {
    
    long int i=0,j=0,k=0,m=0,x=0,d=0,r=0;
    cin>>i>>j>>k;
    for(m=i;m<=j;m++)
    {
        r=0;
        while(m!=0)
        {
            d=m%10;
            r=r*10+d;
            m=m/10;
        }
        if((abs(r-m)%k)==0)
            x++;
    }
    cout<<x;
    return 0;
}
      • non_programmer + 1 comment

        Dude, you are using same m in your code... which will keep on becoming zero after completion from while loop and it will never be equal to j, better try out with this:

        include

        include

        using namespace std; int main() {

        long int i=0,j=0,k=0,m=0,x=0,d=0,r=0,m1=0;
cin>>i>>j>>k;
for(m=i;m<=j;m++)
{
    r=0;
    m1=m;
    while(m1!=0)
    {
        d=m1%10;
        r=r*10+d;
        m1=m1/10;
    }
    if((abs(r-m)%k)==0)
        x++;
}
cout<<x;
return 0;

        } I hope you got what's wrong.

        • UtkarshSWG + 0 comments

          thanks dude...I got it

      • nayan_7991 + 0 comments

        in this when the loop run for the first time the vue of m becomes 0. so we again give the value of i to m and so Infinite loop runs

    • yashwant97 + 0 comments

      sum=(sum*10)+rem; i dint understand this line can u pls help me out?

    • jluisg_23 + 0 comments

      I did it using conversion to string, but now that I see your solution, yours is simpler and faster. I share mine anyways:

      #include <stdio.h>
#include <stdlib.h>

int reversed(int a)
{
    char c, *ptr_b, *ptr_e;
    char buff[12];
    int b;
    
    //Integer to string
    sprintf(buff, "%d", a);
    
    //Reversing string
    ptr_b = buff;
    ptr_e = buff;
    while(*ptr_e){           //Moving ptr_e to point the last char in the string
        ++ptr_e;
    }
    --ptr_e;
    while(ptr_b < ptr_e){  //Reversing
        c = *ptr_b;
        *ptr_b = *ptr_e;
        *ptr_e = c;
        ++ptr_b;
        --ptr_e;
    }
    
    //String to integer
    sscanf(buff, "%d", &b);
    
    return b;
}


int main()
{
    int i, j, k, rev, diff, count = 0;
    
    //Input
    scanf("%d %d %d", &i, &j, &k);
    
    //Counting
    for(int ii = i; ii <= j; ++ii){
        rev = reversed(ii);
        diff = abs(ii-rev);
        if(diff%k == 0) ++count;
    }

    //Output
    printf("%d\n", count);
    
    return 0;
}
    • AGRAWALTUSHAR27 + 0 comments

      Thanks man! You have cleared my confusion.