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int beautifulDays(int i, int j, int k) {
int num,count=0,gn;
int quo, newNum = 0, x = 0;
for (int x = i; x <= j ; x++)
{
num = x; //make sure to assign this
newNum = 0;
//For reversing no
while (num != 0)
{
quo = num % 10;
newNum = 10 * newNum + quo;
num = num / 10;
}
gn = abs(x- newNum);
if (gn%k==0)
{
count++;
}
}
return count;
}
the correct code for reversing (from above commented code)
num=x //assignment of the temp number
while(num!=0)
{
//code
}
if u dont assign a new variable(num)
that leads to changing the value of for loop initiailizer (x) to 0 at end of the loop ,which makes the loop infinite.
int reverse(int n){
int rev=0;
int rem=0;
while (n!=0){
rem=n%10;
rev=rev*10+rem;
n/=10;
}
cout<< rev<< endl;
return rev;
}
// Complete the beautifulDays function below.
int beautifulDays(int i, int j, int k) {
int ctr=0;
for (int x =i;x<=j;x++){
int rev=reverse(x);
if (abs(rev-x)%k==0){
ctr+=1;
}
}
return ctr;
// Complete the beautifulDays function below.
static int beautifulDays(int i, int j, int k) {
int c=0,num;
int revno=0;
int temp,gn;
for(int l=i;l<=j;l++)
{
num=l;
temp=0;
while(num!=0)
{
temp=num%10;
revno=revno*10+temp;
num=num/10;
}
gn=Math.abs(l-revno);
if(gn%k == 0)
{
c++;
}
} return c;
}
private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) throws IOException {
BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
String[] ijk = scanner.nextLine().split(" ");
int i = Integer.parseInt(ijk[0]);
int j = Integer.parseInt(ijk[1]);
int k = Integer.parseInt(ijk[2]);
int result = beautifulDays(i, j, k);
bufferedWriter.write(String.valueOf(result));
bufferedWriter.newLine();
bufferedWriter.close();
scanner.close();
}
}
(I followed the same approach then why ist showing wrong answer??)
Beautiful Days at the Movies
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please explain the mistake clearly bro
int beautifulDays(int i, int j, int k) { int num,count=0,gn; int quo, newNum = 0, x = 0; for (int x = i; x <= j ; x++) { num = x; //make sure to assign this newNum = 0; //For reversing no while (num != 0) { quo = num % 10; newNum = 10 * newNum + quo; num = num / 10; } gn = abs(x- newNum); if (gn%k==0) { count++; } } return count; }
the correct code for reversing (from above commented code)
num=x //assignment of the temp number while(num!=0) { //code } if u dont assign a new variable(num) that leads to changing the value of for loop initiailizer (x) to 0 at end of the loop ,which makes the loop infinite.
thank u bro!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
but i made another function for reversing the number so that value of x doesnt change. still i am having same trouble of time out.
show me the code which u written
int reverse(int n){ int rev=0; int rem=0; while (n!=0){ rem=n%10; rev=rev*10+rem; n/=10; } cout<< rev<< endl; return rev; } // Complete the beautifulDays function below. int beautifulDays(int i, int j, int k) { int ctr=0; for (int x =i;x<=j;x++){
Same test cases are getting timeOut. use string methods to reverse the int and it is much faster.
import java.io.; import java.math.; import java.security.; import java.text.; import java.util.; import java.util.concurrent.; import java.util.regex.*;
public class Solution {
}
(I followed the same approach then why ist showing wrong answer??)
Before the beginning of while loop, make sure you do revno=0;
Thank You Sir.I got the problem !
nice