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because lcm(b)~1.77*10^19, which is out of integer range, even long long range. So integer overflow happens (https://en.wikipedia.org/wiki/Integer_overflow) // integer range is from -2^31 to 2^31-1~2.15*10^9, long long range is from -2^61 to 2^61-1~3.21*10^18.
I've noticed hackerRank has poor tests. That is why such solutions pass tests.
Specifically in this task variable l can not be greater than 100. So I recommend you return 101, when result variable from lcm fuction is coming greater than 100. It will prevent for loop which count "count" variable
So sorry for my poor english, it is not my native language
When you overflow an integer, it will wrap around. At the assembly level you can check to see the zero and overflow flags have been set. So an overflow on a signed int can set the bit that indicates that the number is negative.
Between Two Sets
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for this case, why is lcm coming negative?
because lcm(b)~1.77*10^19, which is out of integer range, even long long range. So integer overflow happens (https://en.wikipedia.org/wiki/Integer_overflow) // integer range is from -2^31 to 2^31-1~2.15*10^9, long long range is from -2^61 to 2^61-1~3.21*10^18.
Yes i have understood. But how can we proceed with program when our lcm is coming to be negative. Shouldnt the program logic give wrong results then?
I've noticed hackerRank has poor tests. That is why such solutions pass tests. Specifically in this task variable l can not be greater than 100. So I recommend you return 101, when result variable from lcm fuction is coming greater than 100. It will prevent for loop which count "count" variable So sorry for my poor english, it is not my native language
ty
you are welcome
yeah i too feel that hkrnk has poor tstcases
When you overflow an integer, it will wrap around. At the assembly level you can check to see the zero and overflow flags have been set. So an overflow on a signed int can set the bit that indicates that the number is negative.