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  1. Practice
  2. C++
  3. Introduction
  4. For Loop
  5. Discussions

For Loop

  • bergart11 + 11 comments

    Great code, I like it.

    Here is mine:

    #include <iostream>
#include <cstdio>
using namespace std;

int main() {
    // Complete the code.
    int a,b;
    int n=0;
    string intMap[9]= {"one", "two","three","four","five","six","seven","eight","nine"};
    
    cin>>a>>b;
    
    if ((a<=9)&&(b<=9)){ 
       for(n=a;n<=b;n++){
            cout << intMap[n-1]<<endl; 
        } }
    else if ((a<=9)&&(b>9)){    
        for(n=a;n<=9;n++){
            cout<<intMap[n-1]<<endl;
        }    
        for(n=10;n<=b;n++){    
            if (n%2==0){
                cout<<"even"<<endl;
            }
             else {
                 cout<<"odd"<<endl;
             }
         }
  }
    
    else {
        for(n=a;n<=b;n++){
            if (n%2==0){
                cout<<"even"<<endl;
            }
             else {
                 cout<<"odd"<<endl;
             }
        }
            
    }
    
    
    return 0;
}
    • piyushp0541 + 4 comments

      for(n=10;n<=b;n++){
      if (n%2==0){ cout<<"even"< 

               what these lines are performing can anyone explain please 
....
      • Vexify + 2 comments
        //Compares the values of a, b with 9 and if values <= 9 then
//Prints all values from 'a' uptill 'b' in string format
if ((a<=9)&&(b<=9)){ 
       for(n=a;n<=b;n++){
            cout << intMap[n-1]<<endl; 
        } }
    //Compares the values of a, b with 9
    //And if the value of a <= 9 and value of b > 9 then....
    else if ((a<=9)&&(b>9)){    
        //Prints all the values starting from 'a' uptill 9
        //in string format and then....
        for(n=a;n<=9;n++){
            cout<<intMap[n-1]<<endl;
        }
        //For values which are greater than 9 and <= to 'b'
        //Prints 'even' or 'odd' for them
        for(n=10;n<=b;n++){    
            if (n%2==0){
                cout<<"even"<<endl;
            }
             else {
                 cout<<"odd"<<endl;
             }
         }
  }

Hope that helps.
        • samarthchadda_i1 + 0 comments

          why you have used intmap[n-1]

        • fatursetiawan80 + 0 comments

          thank you so much...

      • sanjay_kanakkot + 0 comments
        [deleted]
      • sanjay_kanakkot + 0 comments

        for(n=10;n<=b;n++) checking the value of n is less than b if(n%2==0) suppose the value of n you given is 10 if statement will find the remainder by using the modulus % that is n%2 10%2 just divide the reminder will always be zero which means if its divisible by 2 it is even number..

      • klausskent17 + 0 comments

        you have a for loop and it start counting from 10 , after check the condition if n is inferior or egal to b , when it is true it increment the value of n ... if n%2 == 0 , means if n is divisible by 2 , he will display even I hope it helps you :-)

    • eshank_tiwari + 0 comments
      [deleted]
    • abhisheksud96 + 0 comments

      what is the use of String intMap[]

    • vasu71051 + 1 comment

      can u please explain the string type in C++ .I searched it over net but didn't got the satisfying result. According to me String is an array of char but you used it as a predefined data-type.how?

      • singla_skanika + 0 comments

        are you askin about its library file? If that is true,

        include

    • talalawaiskhan + 0 comments

      Love your code but arrays havent been introduced here yet! so why did u use it? Cant it be done without arrays?

    • V0dK6 + 0 comments

      After your "else if", your "else" statement can be skipped. It will pass all tests cases without. Just saying... Your code is great by the way and pass all tests cases anyway ;-)

    • shuklarituraj9 + 3 comments

      Much simple, try this.

      #include <iostream>
#include <cstdio>
using namespace std;

int main() {
    int i,c,b;
    string a[11]={"even","odd","one","two","three","four","five","six","seven","eight","nine"};
    cin>>c>>b;
    for(i=c;i<=b;i++)
    {
        if((i>9) && (i%2==0))  cout<<a[0]<<endl;
        else if((i>9) && (i%2!=0)) cout<<a[1]<<endl;
        else    cout<<a[i+1]<<endl;
    }
    return 0;
}
      • annufranci + 0 comments
        [deleted]
      • AuCcH + 0 comments

        it helped

      • aamirsohail_as75 + 0 comments

        sir, can you explain in easy way, please

    • codertoaster + 1 comment

      Unnecessarily making it so long and unreadable.

      string words[]={"one","two","three","four","five","six","seven","eight","nine"};
    for(int n=a;n<=b;n++)
    { 
        if(n>9)
            if(n%2==0)
                printf("even\n");
            else
                printf("odd\n");
        else
            printf("%s\n",words[n-1].c_str());
    }
      • shuklarituraj9 + 0 comments

        I think it is better than writing multiple "if-else" and one who can code can read it without any trouble.

    • vipinarmy100 + 0 comments

      what for the values when a and b both are greater than 9

    • Prodyte + 0 comments

      pretty long one.

    • sprudra2001 + 0 comments

      exactly wwhat i did nut there are slightly better codes available we wont need those many if else and for loops inside.