We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Practice
  2. C++
  3. Strings
  4. Strings
  5. Discussions

Strings

Sort 489 Discussions, By:

  • melroy_tellis
     + 17 comments
    #include <bits/stdc++.h>

using namespace std;

int main()
{
    string a, b;
    cin >> a >> b;
    
    cout << a.length() << ' ' << b.length() << endl;
    
    cout << a + b << endl;
    
    swap( a[0], b[0] );
    cout << a << ' ' <<  b << endl;
    
    return 0;
}

  • rock29520
     + 9 comments

    I hope this will Help you to think something new.don't copy paste. }

    #include <iostream>
#include <string>
using namespace std;

int main() {
   string a,b;
    string tmp;
    cin>>a;
    cin>>b;
    cout<<a.size()<<" "<<b.size()<<endl<<(a+b)<<endl;
    tmp[0]=a[0];
    tmp[1]=b[0];
    a[0]=tmp[1];
    b[0]=tmp[0];
    cout<<a<<" ";
    cout<<b;
  
    return 0;
}

  • A_Goerlitz
     + 3 comments

    love to use XOR swapping:

    a[0] = a[0] ^ b[0];
b[0] = b[0] ^ a[0];
a[0] = a[0] ^ b[0];

    :-)

  • Ethan13310
     + 0 comments

    Here's my answer:

    #include <iostream>
#include <string>
#include <utility> // std::swap

int main()
{
    std::string a{};
    std::string b{};
    std::cin >> a >> b;
    
    std::cout << a.size() << ' ' << b.size() << std::endl;
    std::cout << a + b << std::endl;
    // Don't forget to check if both strings are not null
    if (a.size() > 0 && b.size() > 0)
    {
        std::swap(a[0], b[0]);
        std::cout << a << ' ' << b << std::endl;
    }
    return 0;
}

  • goetz
     + 1 comment

    Looks like the compiler is not properly configured to handle the input. Try this with getline() and you will find an extra \n character is captured. I don't care enough to verify (cin works just fine), but this is probably a Window/Linux/OSX issue with end-of-line (\r\n, \n, \r respectively). Its like the input was created in Windows and the compiler is on a Linux machine.

    Still, I could be wrong about this.

Load more conversations