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Cats and a Mouse

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  • grbz_kerem
    2 months ago+ 1 comment

    JavaScript One-Line Solution

    function catAndMouse(x, y, z) {
      return Math.abs(z - x) === Math.abs(z - y) ? "Mouse C" : Math.abs(z - x) > Math.abs(z - y) ? "Cat B" : "Cat A"
    }
    
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