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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Cats and a Mouse
  5. Discussions

Cats and a Mouse

  • grbz_kerem
     + 1 comment

    JavaScript One-Line Solution

    function catAndMouse(x, y, z) {
  return Math.abs(z - x) === Math.abs(z - y) ? "Mouse C" : Math.abs(z - x) > Math.abs(z - y) ? "Cat B" : "Cat A"
}