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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Cats and a Mouse
  5. Discussions

Cats and a Mouse

  • mrjackyliang
     + 1 comment

    JavaScript solution:

    /**
 * x - cat a
 * y - cat b
 * z - mouse
 */
function catAndMouse(x, y, z) {
    const catA = Math.abs(x - z);
    const catB = Math.abs(y - z);
    
    console.log(catA, catB);
    
    if (catA === catB) {
        return 'Mouse C';
    } else if (catA < catB) {
        return 'Cat A';
    } else if (catA > catB) {
        return 'Cat B';
    }
}