We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Collections
  4. collections.Counter()
  5. Discussions

collections.Counter()

  • tiwarirahul479
     + 0 comments

    Here is the most optimised and cleaner code (without constraint) for this problem:-

    from collections import Counter
no_of_shoes = int(input())
size_list = map(int, input().split(" "))
total_customers = int(input())

size_dict = Counter(size_list)

earning = 0
for j in range(total_customers):
    i = list(map(int, input().split(" ")))
    if size_dict[i[0]]:
        earning += i[1]
        size_dict[i[0]] -= 1

print(earning)

    `