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  1. Prepare
  2. Python
  3. Itertools
  4. Compress the String!
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Compress the String!

  • rohitambasta_ii1
     + 0 comments

    Core Python code (Without Built-in function)- We will appreciate itertools module some other time :

    string= input()

lst= [element for element in string]

count= 1

prev= lst[0]

for i in range(1, len(lst)):
    if lst[i] == prev:
        count = count + 1

    else:
        print(f"({count}, {prev})", end= " ")
        prev= lst[i]
        count = 1

print(f"({count}, {prev})")