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For C# LINQ
int result = arr.Aggregate(1, (a, b) => (b * a)%1234567);
for Python:
reduce(lambda x,y: (x*y)%1234567,l)
Connecting Towns
You are viewing a single comment's thread. Return to all comments →
For C# LINQ
for Python:
reduce(lambda x,y: (x*y)%1234567,l)