We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Artificial Intelligence
  3. Digital Image Analysis
  4. Morphological Operations: Dilation
  5. Discussions

Morphological Operations: Dilation

Sort by

recency

|

8 Discussions

|

  • KingEdoYamatoIII
     + 0 comments

    Could have used Plain Text instead as an easier option. Psst, the answer is 59 in the Plain Text.

  • ricardo_ulloa_v
     + 0 comments

    DON'T UNDERSTAND WHY RUNTIME ERROR, MY PROGRAM IS IN PYTHON3

                    
import cv2
import numpy as np

im = np.array([[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,  ],
                [ 0, 1, 1, 1, 1, 1, 1, 1, 0, 0,  ],
                [ 0, 0, 0, 0, 1, 1, 1, 1, 0, 0,  ],
                [ 0, 0, 0, 0, 1, 1, 1, 1, 0, 0,  ],
                [ 0, 0, 0, 1, 1, 1, 1, 1, 0, 0,  ],
                [ 0, 0, 0, 0, 1, 1, 1, 1, 0, 0,  ],
                [ 0, 0, 0, 1, 1, 0, 0, 0, 0, 0,  ],
                [ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,  ],
                [ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,  ]], dtype = np.uint8)

kernel = np.ones((3,3), dtype = np.uint8)


img_dilation = cv2.dilate(im, kernel, iterations=1) 

print(int(np.sum((img_dilation == 1))))

  • singhjaitawat824
     + 0 comments

    import numpy as np

    img = np.array([ [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 1, 1, 1, 1, 1, 1, 1, 0, 0], [0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 0, 0, 1, 1, 1, 1, 1, 0, 0], [0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 0, 0, 1, 1, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] ])

    def dilation(image): count = 0 

    for i in range(image.shape[0] - 1): 
    for j in range(image.shape[1] - 1): 
        if image[i][j] == 1: 
            count += 1
        elif (
            image[i-1][j] == 1 or 
            image[i+1][j] == 1 or 
            image[i][j-1] == 1 or 
            image[i][j+1] == 1 or 
            image[i-1][j-1] == 1 or 
            image[i-1][j+1] == 1 or 
            image[i+1][j-1] == 1 or 
            image[i+1][j+1] == 1
        ): 
            count += 1

return count

    result = dilation(img) print(int(result))

  • rahulkumeriya
     + 0 comments
    import numpy as np
import matplotlib.pyplot as plt
from skimage.io import imread, imshow
from skimage.draw import disk
from skimage.morphology import (erosion, dilation, closing, opening,
                                area_closing, area_opening)
from skimage.color import rgb2gray

a = np.array([
    [0,0,0,0,0,0,0,0,0,0],
    [0,1,1,1,1,1,1,1,0,0],
    [0,0,0,0,1,1,1,1,0,0],
    [0,0,0,0,1,1,1,1,0,0],
    [0,0,0,1,1,1,1,1,0,0],
    [0,0,0,0,1,1,1,1,0,0],
    [0,0,0,1,1,0,0,0,0,0],
    [0,0,0,0,0,0,0,0,0,0],
    [0,0,0,0,0,0,0,0,0,0]
])

s = np.array([
        [1,1,1],
        [1,1,1],
        [1,1,1]])

unique, freq = np.unique(dilation(a,s), return_counts=True)
print(freq[1])

  • mykola_maliaren1
     + 0 comments

    There is no any information about input, can you post instructions?