We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Artificial Intelligence
  3. Digital Image Analysis
  4. Morphological Operations: Dilation
  5. Discussions

Morphological Operations: Dilation

  • singhjaitawat824
     + 0 comments

    import numpy as np

    img = np.array([ [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 1, 1, 1, 1, 1, 1, 1, 0, 0], [0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 0, 0, 1, 1, 1, 1, 1, 0, 0], [0, 0, 0, 0, 1, 1, 1, 1, 0, 0], [0, 0, 0, 1, 1, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] ])

    def dilation(image): count = 0 

    for i in range(image.shape[0] - 1): 
    for j in range(image.shape[1] - 1): 
        if image[i][j] == 1: 
            count += 1
        elif (
            image[i-1][j] == 1 or 
            image[i+1][j] == 1 or 
            image[i][j-1] == 1 or 
            image[i][j+1] == 1 or 
            image[i-1][j-1] == 1 or 
            image[i-1][j+1] == 1 or 
            image[i+1][j-1] == 1 or 
            image[i+1][j+1] == 1
        ): 
            count += 1

return count

    result = dilation(img) print(int(result))