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ar[i] would be less tha ar[j] always as ar[j] is initialized as i+1. So it will always be 1 value bigger than i.
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Divisible Sum Pairs
You are viewing a single comment's thread. Return to all comments →
ar[i] would be less tha ar[j] always as ar[j] is initialized as i+1. So it will always be 1 value bigger than i.