#return min((p//2), ((n//2)-(p//2)))
'
Type 2:
'
listi = []
    for i in range(0, n+1, 2):
        listi.append((i, i+1))
    for i in range(len(listi)):
        if p in listi[i]:
            front = i
    back = len(listi) - front - 1
    return min(front, back)