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For ORACLE junkies :
select salary*months,count(*) from employee
where salary*months = (select max(salary*months) from employee)
group by salary*months;
This will work faster then using the Having Condition.
Initially I tried using -
select salary*months,count(*) from employee
group by salary*months
having salary*months = (select max(salary*months) from employee);
But in this case the query cost was damn too high because of obvious reasons.
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For ORACLE junkies : select salary*months,count(*) from employee where salary*months = (select max(salary*months) from employee) group by salary*months;
This will work faster then using the Having Condition.
Initially I tried using - select salary*months,count(*) from employee group by salary*months having salary*months = (select max(salary*months) from employee);
But in this case the query cost was damn too high because of obvious reasons.