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Javascript Simple Solution
function getMoneySpent(keyboards, drives, b) { let m = keyboards.length; let n = drives.length; let val = 0; for(let i = 0; i < m; i++){ for(let j = 0; j < n; j++){ if(keyboards[i]+drives[j] <= b && keyboards[i]+drives[j] > val){ val = keyboards[i]+drives[j]; } } } if(val == 0){ return -1; } else{
return val; }
}
Electronics Shop
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Javascript Simple Solution
}