//my js solution

function getMoneySpent(keyboards, drives, b) {
    let sum = 0;
    let budget = []
    for (let i = 0; i < keyboards.length; i++) {
        for (let j = 0; j < drives.length; j++) {
            sum = keyboards[i] + drives[j]
            if (sum <= b) {
                budget.push(sum)
            }
        }
    }
    let result = Math.max(...budget)
    if (budget.length === 0) {
        return -1
    } else {
        return result
    }

}