• + 0 comments
    //my js solution
    
    function getMoneySpent(keyboards, drives, b) {
        let sum = 0;
        let budget = []
        for (let i = 0; i < keyboards.length; i++) {
            for (let j = 0; j < drives.length; j++) {
                sum = keyboards[i] + drives[j]
                if (sum <= b) {
                    budget.push(sum)
                }
            }
        }
        let result = Math.max(...budget)
        if (budget.length === 0) {
            return -1
        } else {
            return result
        }
    
    }