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JS solution
function getMoneySpent(keyboards, drives, b) { if(Math.min(...keyboards)+Math.min(...drives) > b){ return -1 } const inBudget = []; for(let i = 0; i < keyboards.length; i++){ for(let j = 0; j < drives.length; j++){ const sum = keyboards[i]+drives[j]; if(sum <= b){ inBudget.push(sum); } } } return Math.max(...inBudget); }
Electronics Shop
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JS solution