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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Fair Rations
  5. Discussions

Fair Rations

  • erfan74sh
     + 0 comments

    my solution in Javascript:

    if the count of odd numbers are odd it should return 'NO', and...

    function fairRations(B) {
    let count = 0;
    if (B.filter((v) => v % 2 == 1).length % 2 == 1) {
        return "NO";
    } else {
        B.forEach((v, i) => {
            if (v % 2 == 1) {
                B[i]++;
                B[i + 1]++;
                count += 2;
            }
        });
    }
    return count;
}