Find Angle MBC

  • + 0 comments

    select id,age,coins_needed,power from( select rank() over(partition by power,age order by coins_needed) rno,id,age,coins_needed,power from wands w inner join wands_property p on w.code=p.code where is_evil=0 )x where x.rno=1 order by power desc,age desc;