Find Angle MBC

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    We can Solve this problem by using a property: ** That a median on the hypotenuse divides the right angled triangle in two isoceles triangle.** * Means AM=BM=CM * So, ∡MBC = ∡MCB

    Now find ∡MCB [You can use 'tan' ]

    import math AB = int(raw_input()) BC = int(raw_input()) print str(int(round(math.degrees(math.atan2(AB,BC)))))+'°'