• + 0 comments

    That simple version and u dont need to handling every case. If u have any qs I'am Here.

    #include <stdio.h>
    int main(void)
    {
        int a, b;
        scanf("%d\n%d", &a ,&b);
        const char *nbword[10] = {"zero", "one", "two", "three", "four" ,"five", "six", "seven" ,"eight", "nine"};
        
        int i = a;
        while (i <= b)
        {
            if (i >= 1 && i <= 9)
                printf("%s\n", nbword[i]);
            else 
            {
                if (!(i % 2 == 0))
                    printf("odd\n");
                else
                    printf("even\n");
            }
            i++;
        }
    

    }