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  1. Practice
  2. Algorithms
  3. Implementation
  4. Grading Students
  5. Discussions

Grading Students

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  • cakerusk + 0 comments

    Java one-liner code :

        System.out.println(grade < 38 || grade % 5 < 3 ? grade : grade + (5 - (grade % 5)));

  • jasonganub + 0 comments

    A simple and clean solution with only one print statement and minimal conditionals.

    if grade >= 38:
    if grade % 5 == 3:
        grade += 2
    elif grade % 5 == 4:
        grade += 1
print(grade)

  • imerljak + 0 comments

    Javascript with ES6 :)

    function solve(grades){
    return grades.map((n) => {
        let diff = 5 - (n % 5);
        if(diff < 3 && n >= 38) {
            n += diff;
        }
        
        return n;
    })
}

  • ikhan77727 + 0 comments

    python solution 

    def gradingStudents(grades):
    return [ i if (i < 38 or i % 5 < 3) else (i + (5 - i%5)) for i in grades]

  • kevinlai31 + 0 comments

    C version is broken btw. main function calls "gradingStudents" with undeclared first argument. change the first argument to "n"

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