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  1. Prepare
  2. Mathematics
  3. Number Theory
  4. Identify Smith Numbers
  5. Discussions

Identify Smith Numbers

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  • h2500030287
     + 0 comments

    simple code

    include

    int isPrime(int n) { if (n < 2) return 0; for (int i = 2; i*i <= n; i++) if (n % i == 0) return 0; return 1; }

    int digitSum(int n) { int s = 0; while (n) s += n % 10, n /= 10; return s; }

    int primeFactorDigitSum(int n) { int s = 0; for (int i = 2; i <= n; i++) { if (isPrime(i)) { while (n % i == 0) { s += digitSum(i); n /= i; } } } return s; }

    int main() { int n; scanf("%d", &n); printf("%d\n", (!isPrime(n) && digitSum(n) == primeFactorDigitSum(n)) ? 1 : 0); return 0; }

  • greenbethany
     + 0 comments

    Great post on Smith Numbers! For those diving deeper into number theory, it's fascinating to see how these numbers bridge the gap between math and patterns. Have you considered how tools like Drift Boss can help visualize complex concepts like these? Utilizing games or puzzles could enhance understanding by making the learning process more interactive. Keep sharing such insightful content!

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     + 0 comments

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     + 0 comments

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  • 2k23_csai2310233
     + 0 comments
    public static int solve(int nn) {
    // Write your code here
                  int ds=0;
        int temp=nn;
        int n=nn;
        List<Integer> a=new ArrayList<>();
        while(temp>0){
            ds+=temp%10;
            temp/=10;
        }
        
         while (n % 2 == 0) {
           a.add(2);
            n /= 2;
        }
        for (int i = 3; i <= Math.sqrt(n); i += 2) {
            while (n % i == 0) {
                a.add(i);
                n /= i;
            }
        }
 
        if (n > 2)
           a.add(n);
        
        
        int fsum=0;
        
        for(int i:a)
        {
            while(i>0){
                fsum+=i%10;
                i=i/10;
            }
        }
        //System.out.println(a);
        if(fsum==ds)
            return 1;
        return 0;
    }