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  1. Practice
  2. Data Structures
  3. Linked Lists
  4. Insert a Node at the Tail of a Linked List
  5. Discussions

Insert a Node at the Tail of a Linked List

  • abbhishek971 + 6 comments

    This is my solution in C++14

    Node* Insert(Node *head,int data)
{
    Node *temp = new Node();
    temp->data = data;
    temp->next = NULL;
   if(head==NULL)
   {
       head = temp;
   }
   else if(head->next==NULL)
   {
            head->next = temp;
            return head;
    }
    else
    {
        Insert(head->next,data);
    }
    return head;
}
    • arkaguin + 0 comments

      thanks

    • neeraj1515_kaus1 + 1 comment

      what is the difference bet Node* temp and Node *temp.?

      • abbhishek971 + 0 comments

        Apologies for the delay in reply.

        There's no difference. Both the notations result in the same identifier declaration.

    • raghuvendra867 + 0 comments

      bro can u explain ur code?

    • abhishekjoshi261 + 0 comments

      solution.cc:46:1: error: ‘Node’ does not name a type; did you mean ‘modf’? Node* Insert(Node head,int data) ^~~~ modf solution.cc: In function ‘int main()’: solution.cc:83:41: error: ‘insertNodeAtTail’ was not declared in this scope SinglyLinkedListNode llist_head = insertNodeAtTail(llist->head, llist_item);

              showing this error code not working
    • shubhvratj + 4 comments

      SinglyLinkedListNode* insertNodeAtTail(SinglyLinkedListNode* head, int data) {

          SinglyLinkedListNode *new_node,*ptr;
    new_node = new SinglyLinkedListNode();
    new_node->data = data;
    new_node->next = NULL;
    if(head == NULL){
        head = new_node;
        return head;
    }else{
        ptr = head;
        while(ptr != NULL){
            ptr = ptr->next;
        }
        ptr->next = new_node;
        new_node->next = NULL;
return head;    
    }

      }

      can you please help me with this code?

      • abhishekjoshi261 + 0 comments

        Node* Insert(Node *head,int data) { struct Node *temp,*tail,*ptr; temp=new Node; temp->data=data; temp->next=NULL; if(head==NULL) { head=temp;} else { ptr=head; while(ptr!=NULL) { tail=ptr; ptr=ptr->next; } tail->next=temp; } return head;

        }

        bro i think you missed the struct function and above is the soln that worked for me pm me if you find any problem

      • asmitaverma + 0 comments
        [deleted]
      • asmitaverma + 2 comments

        Here's my solution in C++14. The class definition of SinglyLinkedListNode specifies that the constructor has an argument which is the data part of the node to be inserted.

        SinglyLinkedListNode* insertNodeAtTail(SinglyLinkedListNode* head, int num){

        SinglyLinkedListNode* node = new SinglyLinkedListNode(num);
node->data = num;
node->next = NULL;

if(head == NULL){
    head = node;
}

else{
    SinglyLinkedListNode* temp;
    temp = head;
    while(temp->next != NULL){
        temp = temp->next;
    }
    temp->next = node;
}

return head;

        }

        • anamalaii + 0 comments

          Thank you

        • alexey_chekhovi1 + 0 comments

          SinglyLinkedListNode* node = new SinglyLinkedListNode(num);

          Works.

          SinglyLinkedListNode *newNode = new SinglyLinkedListNode();

          solution.cc:61:62: error: no matching function for call to ‘SinglyLinkedListNode::SinglyLinkedListNode()

          So we do not have an empty constructor, but do have a constructor with parameters. The one who wrote the background of this task should be immediately exterminated.

      • akkidewangan96 + 0 comments

        new_node = new SinglyLinkedListNode(data);

        try this in 2nd line

    • akkuarora07 + 0 comments

      how can i remove this error?

      solution.cc:47:1: error: ‘Node’ does not name a type; did you mean ‘modf’?

      please help.