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Java Datatypes

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  • hitesh_chopra
    5 years ago+ 0 comments

    My Solution:

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int t=sc.nextInt();
        for(int i=0;i<t;i++)
        {
            try
            {
                long x=sc.nextLong();
                System.out.println(x+" can be fitted in:");
                if(x == (byte)x)System.out.println("* byte");
                if(x == (short)x)System.out.println("* short");
                if(x == (int)x)System.out.println("* int");
                if(x == (long)x)System.out.println("* long");
            }
            catch(Exception e)
            {
                System.out.println(sc.next()+" can't be fitted                  anywhere.");
            }
    
        }
    }
    
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