Java Datatypes

  • + 2 comments

    IF INTEGER TOO LONG ,ERROR COMES FOR ANYONE:

    USE 'L' AT ENDING OF LONG.

    HERE'S HOW IT IS: if(x>=-9223372036854775808L && x<=9223372036854775807L )System.out.println("* long");

    AND UPVOTE IF IT HELPS YOU OUT.