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Java Datatypes

  • prernasharma3011 + 2 comments

    This solution is giving 2 testcases wrong. What is the problem? Can anyone please explain ? 

            Scanner sc = new Scanner(System.in);
    int t=sc.nextInt();

    for(int i=0;i<t;i++)
    {

        try
        {
            long x=sc.nextLong();
            System.out.println(x+" can be fitted in:");
            if(x>=-128 && x<=127)
                System.out.println("* byte");
            //Complete the code
            if(x>=-32768 && x<=32767)
                System.out.println("* short");
            if(x>=Math.pow(-2,31) && x<Math.pow(2,31))
                System.out.println("* int");
            if(x>=Math.pow(-2,63) && x<Math.pow(2,63))
                System.out.println("* long");

        }
        catch(Exception e)
        {
            System.out.println(sc.next()+" can't be fitted anywhere.");
        }

    }
    sc.close();

    }

    • CH_Sai_Pavan + 0 comments

      All test cases have been passed

      There is only one wrong in your code , you just make the last test case as if(x>=Math.pow(-2,63) && x<= Math.pow(2,63)).

      You basically needed to add an equal there, else it wont work.

      Hope this helps

    • mohaiminur + 0 comments

      It will work fine

          Scanner sc = new Scanner(System.in);
    int t=sc.nextInt();

    for(int i=0;i<t;i++)
    {

        try
        {
            long x=sc.nextLong();
            System.out.println(x+" can be fitted in:");
            if(x>=-128 && x<=127)System.out.println("* byte");
            //Complete the code
            if(x>=-32768 && x<=32767)
            System.out.println("* short");
        if(x>=Math.pow(-2,31) && x<Math.pow(2,31))
            System.out.println("* int");
        if(x>=Math.pow(-2,63) && x<=Math.pow(2,63))
            System.out.println("* long");


        }
        catch(Exception e)
        {
            System.out.println(sc.next()+" can't be fitted anywhere.");
        }

    }
}

      }