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  1. Practice
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • Farahmand + 4 comments

    Instead of

    System.out.println("java.util.InputMismatchException");

    we can use:

    System.out.println(e.getClass().getName());
    • taffarelbergamin + 0 comments

      Fine, but what's the point of showing an exception message in a different way than the other? If you use that, it will give you an error when in the division by zero test case.

      Why one exception should show the extra content and the other not? This is not even part of the exercise.

      What they could do if they really want a nice representation of the exceptions, could be we print something like "This is an input mismatch exception" and "This is an arithmetic exception".

      This would force people to know which exceptions could happen and don't use the generic Exception.

    • kencluff + 3 comments

      I did that, but then testcase 2 failed because it wanted "java.lang.ArithmeticException: / by zero" and you just get "java.lang.ArithmeticException" with this trick.

      • sergeief + 0 comments

        you can get "/ by zero" from ecxeption details message

      • amarvadla27 + 3 comments
        try{
            Scanner sc = new Scanner(System.in);
            int x = sc.nextInt();
            int y = sc.nextInt();
            if(y==0)
                throw  new ArithmeticException("/ by zero");
            else
                System.out.println(x/y);
        }
        catch(InputMismatchException e){
            System.out.println(e.getClass().getName());
        }
        
        catch(ArithmeticException e){
            System.out.println(e);
        }

        `

        • bmk9727 + 1 comment

          can please explain this System.out.println(e.getClass().getName());

          • quirkudoe213 + 1 comment

            you prolly already understand this

            • syndicate27 + 0 comments

              Thank you ^_^

        • syndicate27 + 0 comments

          I look this it looks a lot cleaner then writing out the Arithmetic exception in the catch block. Thank you

        • allforcatmohit + 0 comments

          This also works:

          import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

          public class Solution {

          public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
    Scanner sc = new Scanner(System.in);
    try{
        int x = sc.nextInt();
        int y = sc.nextInt();
        try{
            int result = x/y;
            System.out.println(result);
        } catch(Exception e){
            System.out.println("java.lang.ArithmeticException: / by zero");
        }
    } catch(Exception e){
        System.out.println("java.util.InputMismatchException");
    }
}

          }

      • SamratV + 0 comments

        May be because you are using older version of java. In java 8 this code passes all the testcases successfully.

        try
        {
            int a=obj.nextInt();
            int b=obj.nextInt();
            System.out.print(a/b);
        }
        catch(InputMismatchException e)
        {
            System.out.print(e.getClass().getName());
        }
        catch(Exception e)
        {
            System.out.print(e);
        }
    • ItzMv + 1 comment

      Hey can you tell me why the Test case 4th not showing:-

      java.util.InputMismatchException: For input string: "2147483648"

      After using e.getClass().getName()

      • allforcatmohit + 0 comments

        Here when you use e.getClass().getName(), .getClass() method will be returning the class of the exception and as we have used getName() method. we will get the name of the exception class.

        so here :java.util.InputMismatchException: For input string: "2147483648"

        class name is just "java.util.InputMismatchException"

    • aakash_saini_22 + 0 comments

      What is the use of e.getClass().getName()