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Java Exception Handling (Try-catch)

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  • raavishiva3
    2 months ago+ 0 comments
    import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;
    
    public class Solution {
    
        public static void main(String[] args) {
            /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
            
            try{
                Scanner sc = new Scanner(System.in);
                int x  = sc.nextInt();
                int y = sc.nextInt();
                int result = x/y;
                System.out.println(result);
            }
            catch(ArithmeticException ae){
                System.out.println("java.lang.ArithmeticException: / by zero");
            }
            catch(InputMismatchException ime){
                System.out.println("java.util.InputMismatchException");
            }
        }
    }
    
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