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  1. Prepare
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • tao_zhang
     + 1 comment

    Didn't mentioned need to handle different exceptions differently in the question, but apparently that's how they wanted. 

        public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner scanner = new Scanner(System.in);
        try{
            int x = scanner.nextInt();
            int y = scanner.nextInt();
            System.out.println(x/y);
        }catch(Exception e){
            if (e instanceof InputMismatchException){
                System.out.println(e.getClass().getName());
            } else {
                System.out.println(e);
            }
            
        }

    }