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  1. Prepare
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • prakashs_soni_r1
     + 0 comments

    public class Solution {

    public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */

    Scanner scn = new Scanner(System.in);       
    try{
        int x = scn.nextInt();
        int y = scn.nextInt();
        if(y==0)
            {
                System.out.println("java.lang.ArithmeticException: / by zero");
                return;
            }
        System.out.print(x/y);
    }
    catch(Exception e)
    {
        System.out.println("java.util.InputMismatchException"); 
    }       

}

    }