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Scanner s= new Scanner(System.in);
int x=s.nextInt();
int y=s.nextInt();
try{
int z=x/y;
System.out.println(z);
}
catch(InputMismatchException i){
System.out.println(i.getClass().getName());
}catch(Exception ae){
System.out.println(ae+": / by zero");
}
?? why it is not workig for me..since the arithmetic exception already catched..nd hence am just going to print the next following statements?!
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Java Exception Handling (Try-catch)
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Scanner s= new Scanner(System.in); int x=s.nextInt(); int y=s.nextInt();