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  1. Prepare
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • pavima1965
     + 2 comments

    Scanner s= new Scanner(System.in); int x=s.nextInt(); int y=s.nextInt();

        try{
        int z=x/y;
        System.out.println(z);
    }
    catch(InputMismatchException i){
        System.out.println(i.getClass().getName());
    }catch(Exception ae){
        System.out.println(ae+": / by zero");
    }   

    ?? why it is not workig for me..since the arithmetic exception already catched..nd hence am just going to print the next following statements?!