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Java Exception Handling (Try-catch)

  • RodneyShag + 0 comments

    Java solution - passes 100% of test cases

    From my HackerRank solutions.

    import java.util.Scanner;
import java.util.InputMismatchException;

public class Solution {
    public static void main(String[] args) {
    	Scanner scan = new Scanner(System.in);
        try {
            int x = scan.nextInt();
            int y = scan.nextInt();
            System.out.println(x/y);
        } catch (InputMismatchException e) {
            System.out.println(e.getClass().getName());
        } catch (ArithmeticException e) {
            System.out.println(e.getClass().getName() + ": / by zero");
        }
    }
}

    Let me know if you have any questions.