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  1. Prepare
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • amarvadla27
     + 3 comments
    try{
            Scanner sc = new Scanner(System.in);
            int x = sc.nextInt();
            int y = sc.nextInt();
            if(y==0)
                throw  new ArithmeticException("/ by zero");
            else
                System.out.println(x/y);
        }
        catch(InputMismatchException e){
            System.out.println(e.getClass().getName());
        }
        
        catch(ArithmeticException e){
            System.out.println(e);
        }

    `