We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Practice
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • arhankundu99 + 0 comments

    Here is my code...

    import java.util.*;
public class solution
{
    public static void main(String[] args)
    {
        Scanner scan=new Scanner(System.in);
        try
        {
            int a=scan.nextInt();
            int b=scan.nextInt();
            System.out.println(a/b);
        }
        catch(InputMismatchException e)
        {
            System.out.println("java.util.InputMismatchException");
        }
        catch(Exception e)
        {
            System.out.println(e);
        }
    }
}

    Instead of printing java.util.InputMismatchException I got java.util.InputMismatchException: For input string: "2147483648" ,So I made another catch to directly print the exception