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  1. Prepare
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • arhankundu99
     + 0 comments

    Here is my code...

    import java.util.*;
public class solution
{
    public static void main(String[] args)
    {
        Scanner scan=new Scanner(System.in);
        try
        {
            int a=scan.nextInt();
            int b=scan.nextInt();
            System.out.println(a/b);
        }
        catch(InputMismatchException e)
        {
            System.out.println("java.util.InputMismatchException");
        }
        catch(Exception e)
        {
            System.out.println(e);
        }
    }
}

    Instead of printing java.util.InputMismatchException I got java.util.InputMismatchException: For input string: "2147483648" ,So I made another catch to directly print the exception