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  1. Practice
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • murtuza89 + 3 comments

    This worked for me:

    import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        try{
            int x=sc.nextInt();
            int y=sc.nextInt();
            int z=x/y;
            System.out.println(z);
        }catch(InputMismatchException ime){
            System.out.println(ime.getClass().getName());
        }catch(ArithmeticException ae){
            System.out.println(ae.getClass().getName()+": "+ae.getMessage());
        }catch(Exception i){
            System.out.println(i.getMessage());

        }
    }
}
    • kanmanim + 1 comment

      this does not work

      • murtuza89 + 1 comment

        Worked for me :( Its java program by the way. Hope you selected Java in language option on top right side of the editor. Which test case did it failed for you? Did it gave any compilation error? Can you elaborate?

        • satish_paluvai + 2 comments

          perfect solution in java for passing all the test cases :

          public static void main(String[] args) { try{ Scanner s = new Scanner(System.in); System.out.println(s.nextInt()/s.nextInt()); }catch(ArithmeticException e) { System.out.println(e);

          }catch(InputMismatchException e)
    {
    System.out.println(e.getClass().getName());
}
    catch(Exception e)
{
    System.out.println(e.getClass());
}
}
          • pavima1965 + 0 comments

            i used this stub..but,,,while i type by my own way..it doesnn't work :(// how did i get all testcases passed...when i do copy paste method... :(

          • pavima1965 + 2 comments

            Scanner s= new Scanner(System.in); int x=s.nextInt(); int y=s.nextInt();

                try{
        int z=x/y;
        System.out.println(z);
    }
    catch(InputMismatchException i){
        System.out.println(i.getClass().getName());
    }catch(Exception ae){
        System.out.println(ae+": / by zero");
    }   

    ?? why it is not workig for me..since the arithmetic exception already catched..nd hence am just going to print the next following statements?!
            • viktor_kirjanov + 1 comment
              int x=s.nextInt(); 
int y=s.nextInt();

should be within try{}
              • damini123 + 1 comment

                yeah it worked.. but can you tell me why is it so??

                • asheslaw + 0 comments

                  InputMismatchException is an Exception thrown by Scanner class while taking inputs. The statements in which x and y are taking values from object of Scanner class should be within try block to catch that exception.

            • Priyanka_das + 0 comments

              You don't need append ": / by zero"

    • simran1707 + 0 comments

      Thanks a lot.It worked for me.But It will also work if u don't use the last catch.

    • Kajalgoel + 0 comments

      why do we need to print - System.out.println(ae.getClass().getName()+": "+ae.getMessage()); and not directly the exception object?