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  1. Practice
  2. Java
  3. Introduction
  4. Java If-Else
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Java If-Else

  • ankitcoder28 + 2 comments

    1 ≤ N ≤ 100 you forgot this constraints if number is 101

    • inanutshellus + 2 comments

      I didn't forget it, it's just not defined as to what I'm supposed to do with 101. My reading of the "constraints" was that the inputs would be between 1 and 100... If the author is now failing you for not taking into account the constraint he should specify what should happen when you're outside the bounds. e.g. throw an exception or print nothing.

      • SanjanaKapoor + 1 comment

        Yeah. It is not mentioned what to do if the number is not between 1 and 100. I am getting errors in test case 3 and 7 for my code which is similar to this one. I dont understand what shud be done.

        • inanutshellus + 2 comments

          Unless the test cases changed, you don't have to account for input outside the range.

          • jangapavanyadav + 12 comments

            import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

            public class Solution {


    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";
        if(n%2==1 || ( (n%2==0) && (n>=6 && n <= 20 ) ) ){
          ans = "Weird";
        }
        else{
            ans = "Not Weird";
           //Complete the code

        }
        System.out.println(ans);

    }
}
            • karthikkrishna97 + 1 comment

              super

            • raghubobba123 + 0 comments
              [deleted]
            • marcyvanbeguide7 + 1 comment

              wow i love your reasonning

            • rajesh96 + 1 comment

              thanks jangapavanyadav

            • tusharbz7276 + 3 comments

              you dont need to add (n%2==0) in if(n%2==1 || ( (n%2==0) && (n>=6 && n <= 20 ) ) ) statement as it is not to checking whether the number is even. we need to check only that number is odd so (n%2==1) is important and number is in bitween 6 to 20. if this doesnot follow go to direct else statement. i ran without (n%2==0) statement and it ran perfectly.

              • jangapavanyadav + 2 comments

                are you kidding :-p , If n is even and in the inclusive range of 6 to 20, print Weird, so you didn't check for the even condition and if nis in the range or 6 to 20 you are printing wired, which is wrong

                • tusharbz7276 + 1 comment

                  No i agree with you that it should check the even condition but i dont know what is wrong with the hackerank testing arlgorithm that it is only considering number between 6 to 20(irrespective of even or odd).Go ahead submit the code without n%2==0 condition it does follow all test cases correctly.Thats why i said code is not asking you to check even condition.

                  • kaushik_dushyan1 + 0 comments

                    Well even I added n%2==0 condition but we do not need to. As it has been said that if n is odd it is weird and if even numbers between 6-20 are weird then it doesnt matter that the number is even or odd in 6-20 as odd numbers are already weird with the condition n%2==1. So we can have if(n%2==1 || (n>=6 && n<=20)) for the weird condition.

                • chandradhargowt1 + 0 comments

                  || is a short hand operator. If the left side is evaluated to true, it doesnt even evaluate the right side expression. If a number is odd, the right side expression isnt even evaluated - if the number isnt odd, then it must be even right? why bother adding n%2==0 again?

              • lohithrathode + 0 comments
                [deleted]
              • Roy_Vandana + 0 comments

                EXACTLY

            • nzdvorak + 0 comments

              You don't need n%2==0. If it's between 6 and 20 inclusive it's Weird. Period. Doesn't matter if it's even or odd.

            • zarana_sheth + 3 comments
                          if(n%2==1 || (n%2==0) && (n>=6 && n<=20) ){
                ans = "Weird";
            }
            else{
              if((n%2==0) && (n>=2 && n<=5) || (n>20)){
                 ans="Not Weird";
                }
            }
            System.out.println(ans);
              • akanjaniuuu + 0 comments

                have you compiled this programme in this website complier?

              • trashdatos + 0 comments
                        String ans="Not Weird";
        if(n%2==1){
          ans = "Weird";
        }
        else{

           if (n>=6 && n<=20)
           {
             ans="Weird";
           }
         }
              • freddie_archie + 0 comments

                worked pefectly!; thanks!!, will study this one more, still a beginner at this.

            • jkalandarov + 0 comments

              Can you explain us how you did this in simpler way? Thanks for being super!

            • imtheone + 3 comments

              The questions says n is even and and between 6 to 20 , by this logic even 7,9,11,13,15,17,19 will print "weird " .? Please expalin .?

              (n>=6 && n <= 20 )
              • reshmav912 + 0 comments

                you have to print odd numbers as well as even numbers in the range of 6 to 20 as weird. to find the even numbers you have to check if n%2==0

              • reshmav912 + 5 comments

                import java.io.; import java.util.;

                public class Solution {

    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";

        if(n>=1 && n<=100){
            if(n%2==1){
                ans = "Weird";
            }
            else{
                if(n>=2 && n<=5 ){
                   ans= "Not Weird";
                }
                else if (n>=6 && n<=20){
                    ans = "Weird";
                }
                else if(n>20) {
                    ans = "Not Weird";
                }
            }
        }
        else{
            ans="Invalid no! Enter a number between 1 and 100.";
        }

        System.out.println(ans);

    }
}
                • nanidinesh789 + 0 comments

                  It is correct.

                • StormSoundar + 0 comments

                  Tq dude...

                • ganesh1towhg + 0 comments

                  I recently joined a java development company, and this was very useful in my daily works. Thanks for sharing.

                • mehakkaur2212 + 0 comments

                  It is showing error for test case 4. Please help.

                • sangsing126 + 0 comments

                  String ans=""; --> what's that, please explain

              • abdul_m_talha + 0 comments

                check the if condition..if the number is odd it will print weird and skip the else part. if the 'if' part proves false then by default the number is even ,it will enter the else loop to check for the limit condition and those numbers might be 6,8,10,12,14,16,18,20

            • ahmedayad45 + 0 comments

              where the second condition the number between 2 to 5 ?

            • Manish8087 + 0 comments

              thanks bro...!!

            • sudhanshuprogram + 0 comments

              greAT

          • bhumikadesai17 + 0 comments

            If we dont put the constraints, it is not letting us pass the challenge. I dont know how to put constraints for values.

      • klin6410 + 0 comments

        cool

    • riyaksp + 1 comment

      i have one error for this program .pls give solution.