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  1. Practice
  2. Java
  3. Introduction
  4. Java If-Else
  5. Discussions

Java If-Else

  • reshmav912 + 6 comments

    import java.io.; import java.util.;

    public class Solution {

    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";

        if(n>=1 && n<=100){
            if(n%2==1){
                ans = "Weird";
            }
            else{
                if(n>=2 && n<=5 ){
                   ans= "Not Weird";
                }
                else if (n>=6 && n<=20){
                    ans = "Weird";
                }
                else if(n>20) {
                    ans = "Not Weird";
                }
            }
        }
        else{
            ans="Invalid no! Enter a number between 1 and 100.";
        }

        System.out.println(ans);

    }
}
    • nanidinesh789 + 0 comments

      It is correct.

    • StormSoundar + 0 comments

      Tq dude...

    • ganesh1towhg + 0 comments

      I recently joined a java development company, and this was very useful in my daily works. Thanks for sharing.

    • mehakkaur2212 + 0 comments

      It is showing error for test case 4. Please help.

    • sangsing126 + 0 comments

      String ans=""; --> what's that, please explain

    • gaurav17791 + 0 comments

      getting error for test case 2: In which for digit 4 error is showing.

      can you explain why is so?

      import java.util.Scanner; public class Solution {

      public static void main(String[] args) {

    Scanner sc=new Scanner(System.in);
    int n=sc.nextInt();            
    String ans="";
    if(n>=1 && n<=100) {
        if(n%2==1){
            ans = "Weird"; 
        }else if(n%2==0){
            if (n>=2 && n<=5){
                ans = "not Weird"; 

            }else if (n>=6 && n<=20){
                ans = "Weird"; 
            }else if (n>20){
                ans = "Not Weird"; 
            }
        }
    }else{
        ans = "Invalid";
    }
      System.out.println(ans);
}

      }