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  1. Prepare
  2. Java
  3. Introduction
  4. Java Output Formatting
  5. Discussions

Java Output Formatting

  • ece_22becj37
     + 3 comments

    import java.util.Scanner;

    public class Solution {

    public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    System.out.println("================================");
    for (int i = 0; i < 3; i++) {
        String s1 = sc.next();
        int x = sc.nextInt();
        // Corrected formatting
        System.out.printf("%-15s %03d%n", s1, x);
    }
    System.out.println("================================");

    sc.close(); // Close the Scanner to prevent resource leak
}

    } Clould anyone tell me what is the problem in this approach?? mail me on -hpdjoy@gmail.com or most of the social media with user name @hpdjoy