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  • + 0 comments
    def kangaroo(x1, v1, x2, v2):
        return "YES" if (v1 > v2 and ((x2 - x1) % (v1 - v2)) == 0) or (x1 == x2) else "NO"
    
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    def kangaroo(x1, v1, x2, v2): # Write your code here p1 = x1 p2 = x2 distance = x2-x1 ans = 'NO' while p1<=p2 and distance<=x2-x1: if p1==p2: ans = 'YES' break else: p1 = p1 + v1 p2 = p2 + v2 distance = p2-p1 return(ans)

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    Java: (x1+n*v1=x2+n*v2)To solve for n, we rearrange the equation:(n*v1-n*v2=x2-x1)(n*(v1-v2)=x2-x1)(n=(x2-x1)/(v1-v2))

    public static String kangaroo(int x1, int v1, int x2, int v2) { // Write your code here String bool ="NO"; if((v1>v2)&&((x2-x1)%(v1-v2)==0)){ bool = "YES"; } return bool; }

    }

  • + 0 comments
    string kangaroo(int x1,int v1,int x2,int v2){
       if (v2 >= v1)
          return "NO";
       else if ((x2 - x1)%(v1 - v2) == 0)
          return "YES";
       return'NO";
    }
    
    
    
    
    
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