Discussion on Number Line Jumps Challenge

Sort 3217 Discussions, By:

15 hours ago+ 0 comments

def kangaroo(x1, v1, x2, v2):
    # Write your code here
    if (v2>v1):
        return "NO"
    else:
        r = 1
        for i in range(x2-x1):
            if(x1+(v1*r) == x2+(v2*r)):
                return "YES"
            r+=1
        return "NO"

24 hours ago+ 0 comments

Here is my java solution , it is may be big but it is easily understandable solution to beginners so

import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int x1 = sc.nextInt();
        int v1 = sc.nextInt();
        int x2 = sc.nextInt();
        int v2 = sc.nextInt();
        if((x2>x1)&&(v2>v1)||(x2==x1)||(v1==v2)) {
            System.out.print("NO");
        }
        else if((x2>x1)&&(v1>v2)||(x2==x1)||(v1==v2)) {
            for(x1=x1,x2=x2;x1<=x2;x1=x1+v1,x2=x2+v2) {
                if(x1==x2) {
                 System.out.print("YES");
                 x1 = x1;
                 x2 = x2;
                 break;
                }
            }
            if(x1!=x2)
             System.out.print("NO");
        }
        else if((x1>x2)&&(v2>v1)||(x2==x1)||(v1==v2)) {
            for(x1=x1,x2=x2;x2<=x1;x1=x1+v1,x2=x2+v2) {
                if(x1==x2) {
                 System.out.print("YES");
                 x1 = x1;
                 x2 = x2;
                 break;
                }
            }
            if(x1!=x2)
             System.out.print("NO");
        }
        else if((x1>x2)&&(v1>v2)||(x2==x1)||(v1==v2)) {
            for(x1=x1,x2=x2;x1<=x2;x1=x1+v1,x2=x2+v2) {
                if(x1==x2) {
                 System.out.print("YES");
                 x1 = x1;
                 x2 = x2;
                 break;
                }
            }
            if(x1!=x2)
             System.out.print("NO");
        }
    }
}

2 days ago+ 0 comments

python

    n=10000
jump=0
while(n>0):
    if  x1<x2:
        x1+=v1 
        jump+=1
    else:
        x2+=v2
        jump-=1
    if x1==x2 and jump==0:
        return 'YES'
    n-=1
return 'NO'

2 days ago+ 0 comments

just arithmetic progression JS nodeJs

const a = (x1-x2)/(v2-v1)
return a % 1 === 0 && a>=1  ? 'YES' : 'NO'

2 days ago+ 1 comment

c++ use while

    string kangaroo(int x1, int v1, int x2, int v2) {
cin >> x1 >> v1 >> x2 >> v2;
int sum1 = x1, sum2 = x2;
while(sum1<sum2){
    if(sum1 != sum2){
        sum1 += v1;
        sum2 += v2;
    }
}
if(sum1!=sum2)
return "NO";
else return "YES";

}

Load more conversations