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  1. Prepare
  2. Python
  3. Sets
  4. No Idea!
  5. Discussions

No Idea!

  • dk012
     + 1 comment

    Isn't it more efficient to use a for loop? Because sets A and B are disjoint, if you find i in A then you don't need to check it in B. I don't really know list comprehesions, so maybe I'm missing something.

    n, m = input().split()
array = input().split()

pos = set(input().split())
neg = set(input().split())

happy = 0
for a in array:
    if a in pos:
        happy += 1
    elif a in neg:
        happy -= 1

print(happy)