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  1. Practice
  2. Algorithms
  3. Warmup
  4. Plus Minus
  5. Discussions

Plus Minus

  • reddyjahnavi + 7 comments

    This is my code in python 3

    n = int(input().strip())
arr = [1 if int(temp)>0 else -1 if int(temp)<0 else 0 for temp in input().strip().split(' ') ]
print("{0:.6f}".format(arr.count(1)/n))
print("{0:.6f}".format(arr.count(-1)/n))
print("{0:.6f}".format(arr.count(0)/n))
    • LIYifan + 0 comments

      clever

    • Daniel_Ng_XoR + 0 comments

      this solution is really nice, why is it not higher?! congrats;)

    • v_pietro + 0 comments

      f has default precision 6

    • sculltakers111 + 0 comments

      Pretty nice

    • definealexis1401 + 0 comments

      awesome

    • Davidedvd + 0 comments

      Alternatively:

      for x in (zip(*((x > 0, x < 0, x == 0) for x in arr))):
    print('{0:.6f}'.format(sum(x) / len(arr)))
    • vvijayalakshmi21 + 0 comments

      Can someone please explain how this if else sequence works?